Fix joystick driver. Add interruptor support.

Note that the joystick driver doesn't support combined movements (like
left/up or right/down). This should be fixed.
This commit is contained in:
Christian Groessler
2017-02-15 15:45:49 +01:00
parent 6df0ba5244
commit e6530d68dd
6 changed files with 132 additions and 73 deletions

View File

@@ -49,7 +49,7 @@
; ------------------------------------------------------------------------
; Constants
JOY_COUNT = 2 ; Number of joysticks we support
JOY_COUNT = 2 ; Number of joysticks we support
; ------------------------------------------------------------------------
; Code
@@ -66,7 +66,7 @@ JOY_COUNT = 2 ; Number of joysticks we support
INSTALL:
lda #JOY_ERR_OK
ldx #0
; rts ; Fall through
; rts ; Fall through
; ------------------------------------------------------------------------
; UNINSTALL routine. Is called before the driver is removed from memory.
@@ -91,14 +91,14 @@ COUNT:
;
READJOY:
and #1 ; fix joystick number
bne READJOY_1 ; read right joystick
and #1 ; fix joystick number
bne READJOY_1 ; read right joystick
; Read left joystick
ldx ZP_JOY0_DIR
lda ZP_JOY0_BUTTONS
jmp convert ; convert joystick state to sane cc65 values
jmp convert ; convert joystick state to sane cc65 values
; Read right joystick
@@ -108,8 +108,8 @@ READJOY_1:
lda ZP_JOY1_BUTTONS
lsr a
lsr a
;jmp convert ; convert joystick state to sane cc65 values
; fall thru...
;jmp convert ; convert joystick state to sane cc65 values
; fall thru...
; ------------------------------------------------------------------------
; convert: make runtime lib compatible values
@@ -119,7 +119,7 @@ READJOY_1:
convert:
ldy #0
sty retval ; initialize return value
sty retval ; initialize return value
; ------
; buttons:
@@ -127,7 +127,7 @@ convert:
; values were shifted to the right to be identical).
; Why are there two bits indicating a pressed trigger?
; According to the "Second book of programs for the Dick Smith Wizard"
; (pg. 88ff), the left hand fire button gives the value of
; (pg. 88ff), the left hand fire button gives the value of
; %00010001 and the right hand button gives %00100010
; Why two bits? Am I missing something? Can there be cases that just
; one of those bits is set?
@@ -137,7 +137,7 @@ convert:
and #%00010001
beq cnv_1
inc retval ; left button pressed
inc retval ; left button pressed
cnv_1: tya
and #%00100010
@@ -145,45 +145,47 @@ cnv_1: tya
lda #$02
ora retval
sta retval ; right button pressed
sta retval ; right button pressed
; ------
; direction:
cnv_2: txa
; tested with https://sourceforge.net/projects/creativisionemulator
; $49 - %01001001 - up
; $41 - %01000001 - down
; $4D - %01001101 - left
; $45 - %01000101 - right
;
; are these correct? "Second book of programs for the Dick Smith Wizard" pg. 85 says something different
; ignored for now...
; $85 - %10000101 - up + right
; $8D - %10001101 - down + left
; $89 - %10001001 - up + left
; $85 - %10000101 - down + right (emulator bug?)
; tested with https://sourceforge.net/projects/creativisionemulator
; $49 - %01001001 - up
; $41 - %01000001 - down
; $4D - %01001101 - left
; $45 - %01000101 - right
;
; are these correct? "Second book of programs for the Dick Smith Wizard" pg. 85 says something different
; ignored for now...
; $85 - %10000101 - up + right
; $8D - %10001101 - down + left
; $89 - %10001001 - up + left
; $85 - %10000101 - down + right (emulator bug?)
bit testbit ; bit #0 set?
beq done ; no, no direction
bit testbit ; bit #0 set?
beq done ; no, no direction
and #%00001100 ; mask out other bits
tax
lda #%00000100 ; init bitmask
loop: dex
bmi done2
asl a
bne loop
and #%00001100 ; mask out other bits
lsr a
lsr a
tax
lda #%00000100 ; init bitmask
loop: dex
bmi done2
asl a
bne loop
done2: ora retval
rts
done2: ora retval
rts
done: lda retval
rts
done: lda retval
rts
; ------------------------------------------------------------------------
;
.data
testbit:.byte $01
testbit:.byte $01
; ------------------------------------------------------------------------
;